Question

Al convertir 7161 del sistema decimal a base se obtiene ababab, determinar a+b+n​

Answer 1

Explicación paso a paso:

7161 = ababab(n)

7161 = [ab(n)](n⁴+n²+1)

ademas n < 10

(273)(11) = [ab(n)](n⁴+n²+1)

273 = n⁴ + n² + 1

272 = n²(n²+1)

n = 4

77 = ab(n)

11 = ab(4)

11 = 4a + b

a = 2

b = 3

Piden :

a + b + c = 2 + 3 + 4 = 9