Question

ayudemen en esta por favor​

Answer 1

Respuesta:

$\frac{3x}{2} + \frac{2x}{3} = \frac{1 + 3x}{2} \\ \frac{3x \times 3}{2 \times 3 } + \frac{2x \times 2}{3 \times 2} = \frac{1 + 3x \times 3}{2 \times 3} \\ \frac{9x}{6} + \frac{4x}{6} = \frac{1 + 9x}{6} \\ \frac{9x + 4x}{6} = \frac{1 + 9x}{6} \\ \frac{13x}{6} = \frac{1 + 9x}{6} \\ 13x = 1 + 9x \\ 13x - 9x = 1 \\ 4x = 1 \\ x = \frac{1}{4}$