Question

Sen X entre Csc X + Cos Xentre Sec X = 1

Answer 1

Explicación paso a paso:

$\csc(x) = \frac{1}{ \sin(x) }$

$\sec(x) = \frac{1}{ \ \cos (x) }$

$\sin {}^{2} (x) + \cos {}^{2} (x) = 1$

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$\frac{ \sin(x) }{ \csc(x) } + \frac{ \cos(x) }{ \sec(x) } = 1$

$\frac{ \sin(x) }{ \frac{1}{ \sin(x) } } + \frac{ \cos(x) }{ \frac{1}{ \cos(x) } } = 1$

${ \sin {}^{2} (x) } + \cos {}^{2} (x) = 1$

$1 = 1$