Question

si log a=3 y log b =4 calcula
log(a´*b)
log a/b
log a elevado 2
log a^b

Answer 1

Propiedad: log(axb) =Log a + Log b
Luego: 3+4=7
Propiedad: log(a/b) =Log a - Log b
Luego: 3 - 4= - 1
Propiedad: log a² = 2 x Log a
Luego: 2 x 3 = 6
Propiedad: log b(base a) =( log b)/(log a)
Luego: 4/3

Answer 2

Realizando los calculos obtenemos que:

• Log(a*b) = 7
• log(a/b) = -1
• Log(a²) = 6
• Log(aᵇ) =30000

Por propiedades de logaritmo en cualquier base:

1. Log(a*b)  = log(a) + log(b)

2. log(a/b) = log(a) - log(b)

3. Log(aⁿ) = n*log(a)

Tenemos que: log(a) = 3 y log(b) = 4 entonces

Log(a*b) = log(a) + log(b) = 3 + 4 = 7

log(a/b) = log(a) - log(b) = 3 - 4 = -1

Log(a²) = 2*log(a) = 2*3 = 6

Como Log(b) = 4

10^Log(b) = 10⁴ = 10000

b = 10000

Log(aᵇ) = b*log(a) = b*3 = 3*10000 = 30000

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