Question

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(4x) (3x+2)=
(5x) (2x-3)=
(2x) (5x+6)=
(3x) (2x-7)=

Answer 1

(4x) (3x+2)=  $12 x^{2} +8x$

(5x) (2x-3)= $10 x^{2} -15x$

(2x) (5x+6)= $10 x^{2} +12x$

(3x) (2x-7)=$6 x^{2} -21x$