Question

hallar el valor de x en:
$log \sqrt[4]{2} = \frac{ log2 }{x}$
​

Answer 1

Respuesta:

x=4

Explicación paso a paso:

$\log _{10}\left(\sqrt[4]{2}\right)=\frac{\log _{10}\left(2\right)}{x}\\\log _{10}\left(\sqrt[4]{2}\right)x=\frac{\log _{10}\left(2\right)}{x}x\\\frac{1}{4}\log _{10}\left(2\right)x=\log _{10}\left(2\right)\\4\cdot \frac{1}{4}\log _{10}\left(2\right)x=4\log _{10}\left(2\right)\\\log _{10}\left(2\right)x=4\log _{10}\left(2\right)\\\frac{\log _{10}\left(2\right)x}{\log _{10}\left(2\right)}=\frac{4\log _{10}\left(2\right)}{\log _{10}\left(2\right)}\\x=4$

Es muy fácil si lo analizas solo es estar constantemente despejando X