Question

O: 12 X + 32X + 23 = 203 procedimiento por favor DOY CORONA​

Answer 1

Respuesta:

O: 12 X + 32X + 23 = 203

o⋅112x+32x+23−{203}=0  

⊕(32x⋅12x)12x+23−{203}=0

384x2+o12x+23−{203}=0

(384x2+o)+(23⋅12x)12x−{203}=0

384x2+276x+o12x−{203}=0

(384x2+276x+o)−(203⋅12x)12x=0

384x2−2160x+o12x=0

384x2−2160x+o=0,12x≠0

(384)⋅x2+(−2160)⋅x+(o)=0

x=−(−2160)±(−2160)2−4⋅(384)⋅(o)−−−−−−−−−−−−−−−−−−−−−√2⋅(384)

x=2160±4665600−(1536o)−−−−−−−−−−−−−−−√768

x=2160±−1536⊕4665600−−−−−−−−−−−−−−√768

x=2160±(16)⋅−6⊕18225−−−−−−−−−−√768

x=(16)⋅[(135)±−6⊕18225−−−−−−−−−−√](16)⋅(48)

x1=135+−6⊕18225−−−−−−−−−−√48

x2=135−−6⊕18225−−−−−−−−−−√48

12 X + 32X + 23 = 203

(44x+23)−{203}=0  

44x−180=0

(44)⋅x+(−180)=0

x=−(−180)44

x=−(4)⋅(−45)(4)⋅(11)=45⁄11