Question

Calcula (H+) y (OH-) en soluciones:

1. pH= 5.5

2. pOH = 4

3. pH = 1.8

Answer 1

Explicación:

1)

5,5 = -log[H+]

[H+] = 3,162*10^-6 molar

2)

4 = -log[OH-]

[OH-] = 1*10^-4 molar

3)

1,8 = -log[H+]

[H+] = 0,0158 molar