Question

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Answer 1

Respuesta:

-$senB=cosB$

Explicación paso a paso:

-2senB.cosB=$senB^{2}$-2senB.CosB+$cosB^{2}$

-2senB.cosB+2senB.CosB=$senB^{2}$+$cosB^{2}$

0=$senB^{2}$+$cosB^{2}$

0=$sen^{2} B$+$cos^{2} B$

-$sen^{2} B$=$cos^{2} B$

-$senB=cosB$

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O si quieres sera:

$sen^{2} B$=$1-cos^{2} B$

0=$sen^{2} B$+$cos^{2} B$

0=$1-cos^{2} B$+$cos^{2} B$

0=1

0≠1