Question

A √(-24-40).(1-2)
B √-5.15+47.(-3)
C √12.8+25.4

alguien le sale?
​

Answer 1

Respuesta:

$\sqrt{\left(-24-40\right)\cdot \left(1-2\right)}\\\\\\=\sqrt{\left(-64\right)\left(1-2\right)}\\=\sqrt{\left(-64\right)\left(-1\right)}\\=\sqrt{64\cdot \:1}\\=\sqrt{64}\\=\sqrt{8^2}\\=8$

_________________________________________

$\sqrt{-5\cdot 15+47\cdot \left(-3\right)}\\\\\\=\sqrt{-5\cdot \:15-47\cdot \:3}\\=\sqrt{-75-47\cdot \:3}\\=\sqrt{-75-141}\\=\sqrt{-216}\\\\\mathrm{Aplicar\:las\:leyes\:de\:los\:exponentes}:\quad \sqrt{-a}=\sqrt{-1}\sqrt{a}\\\sqrt{-216}=\sqrt{-1}\sqrt{216}\\=\sqrt{-1}\sqrt{216}\\\\\mathrm{Aplicar\:las\:propiedades\:de\:los\:numeros\:imaginarios}:\quad \sqrt{-1}=i\\=\sqrt{216}i\\\\=6\sqrt{6}i\\\\\\\\Resultado=6\sqrt{6}i$

_________________________________________

$\sqrt{12\cdot 8+25\cdot 4}\\\\\\=\sqrt{96+25\cdot \:4}\\=\sqrt{96+100}\\=\sqrt{196}\\=\sqrt{14^2}\\\\\mathrm{Aplicar\:las\:leyes\:de\:los\:exponentes}:\quad \sqrt[n]{a^n}=a\\\sqrt{14^2}=14\\=14\\\\Resultado=14$