Question

(4x7 – 2x6 + 3x) : (x + 2) = método de ruffini ​

Answer 1

Respuesta:

la respuesta es 956 espero!que te ayude

Answer 2

Respuesta:

$\left(4x^7\:-\:2x^6\:+\:3x\right)\::\:\left(x\:+\:2\right)\:$

Dividimos

$\frac{\left(4x^7-2x^6+3x\right)}{\left(x+2\right)}=4x^6+\frac{-10x^6+3x}{x+2}$

$\frac{-10x^6+3x}{x+2}=-10x^5+\frac{20x^5+3x}{x+2}$

$4x^6-10x^5+\frac{20x^5+3x}{x+2}$

Dividimos

$\frac{20x^5+3x}{x+2}=20x^4+\frac{-40x^4+3x}{x+2}$

$4x^6-10x^5+20x^4+\frac{-40x^4+3x}{x+2}$

$\frac{-40x^4+3x}{x+2}=-40x^3+\frac{80x^3+3x}{x+2}$

$4x^6-10x^5+20x^4-40x^3+\frac{80x^3+3x}{x+2}$

Dividimos

$\frac{80x^3+3x}{x+2}=80x^2+\frac{-160x^2+3x}{x+2}$

$4x^6-10x^5+20x^4-40x^3+80x^2+\frac{-160x^2+3x}{x+2}$

$\frac{-160x^2+3x}{x+2}=-160x+\frac{323x}{x+2}$

$4x^6-10x^5+20x^4-40x^3+80x^2-160x+\frac{323x}{x+2}$

Solución

$\frac{323x}{x+2}=323+\frac{-646}{x+2}$

$\boxed{4\text{x}^6-10\text{x}^5+20\text{x}^4-40\text{x}^3+80\text{x}^2-160\text{x}+323-\frac{646}{\text{x}+2}}$

Saludos...