Question

allar el valor de X
$\: a)\sqrt{ x + 5 }= 6$
$d) \sqrt[3]{ x - 12} = - 3$
$c) \sqrt{ 5.x - 1} = 7$
$d) \sqrt[3]{1 - x²}=-2$
me ayudan nose como se allá el valor de X:(​

Answer 1

Respuesta:

Hallar el valor de "x"

a)

$\sqrt{x + 5} = 6\\\\(\sqrt{x+5} )^2 = (6)^2\\\\x + 5 = 36 \\\\x = 36 - 5\\x = 31$

b)

$\sqrt[3]{x-12} = -3\\\\(\sqrt[3]{x-12} )^3 = (-3)^3\\\\x - 12 = -27\\\\x = -27 + 12\\x = -15$

c)

$\sqrt{5x-1} = 7\\\\(\sqrt{5x-1} )^2 = (7)^2\\\\5x - 1 = 49\\\\5x= 49+ 1\\\\5x = 50\\\\x = 50/5\\x = 10$

d)

$\sqrt[3]{1 - x^2} = -2\\\\(\sqrt[3]{1 - x^2} )^3 = (-2)^3\\\\1 - x^2 = -8\\\\1 - x^2 + 8 = 0\\\\-x^2 + 9 = 0\\\\x^2 - 9 = 0\\\\factoras\\\\(x - 3)(x + 3)\\\\x =3 \\\\x= -3$

Explicación paso a paso: