Question

10. Calcule tan(a + b) si:
* cos2a - sec(a + 20°)= 1
* tan(3B - 35°). cot (ß + 15%) = 1​

Answer 1

RESOLUCIÓN:

$cos(2 \alpha) \times sec( \alpha + 20) = 1 \\ 2 \alpha = \alpha + 20 \\ 2 \alpha - \alpha = 20 \\ \alpha = 20$

$tan(3 \beta - 35) \times \cot( \beta + 15) = 1 \\ 3 \beta - 35 = \beta + 15 \\ 3 \beta - \beta = 15 + 35 \\ 2 \beta = 50 \\ \beta = \frac{50}{2} \\ \beta = 25$

$tan( \alpha + \beta ) \\ \tan(20 + 25) \\ \tan(45) \\ 1$

RESPUESTA:

1