Question

NECESITO AYUDA URGENTE

Answer 1

Respuesta:

$1$

$f(3) = {3}^{3} + 2 = 27 + 2 = 29$

$f(2) = {2}^{3} + 2 = 8 + 2 = 10$

$f(1) = {1}^{3} + 2 = 1 + 2 = 3$

$f( \frac{2}{3} ) = {( \frac{2}{3} )}^{3} + 2 = \frac{8}{27} + 2 = 2 \frac{8}{27}$

$f(6) = {6}^{3} + 2 = 216 + 2 = 218$

$2$

$f(3) = {3}^{2} + 2 \times 3 - 2 = 9 + 6 - 2 = 15 - 2 = 13$

$f(2) = {2}^{2} + 2 \times 2 - 2 = 4 + 4 - 2 = 8 - 2 = 6$

$f(1) = {1}^{2} + 2 \times 1 - 2 = 1 + 2 - 2 = 1$

$f( \frac{2}{3} ) = {( \frac{2}{3} )}^{2} + 2 \times \frac{2}{3} - 2 = \frac{4}{9} + \frac{4}{3} - 2 = \frac{4}{9} + \frac{12}{9} - \frac{18}{9} = - \frac{2}{9}$

$f(6) = {6}^{2} + 2 \times 6 - 2 = 36 + 12 - 2 = 48 - 2 = 46$