1.- Resuelve las siguientes Ecuaciones.
X2 - 5x = 0
X2 - 16 = 0
X2 - 49 = 0
2x2 - 18 = 0
3х2 - 11 = 0
-X2 - x = 0
-X2 + 12x = 0
3x2 - 9x = 0
X2 - 2x - 3 = 0

Me ayudan :,v ​

Respuestas

Respuesta dada por: begazocondoriabigail
0

Respuesta:

espero te ayude :D (perdón la demora)

Explicación paso a paso:

1)   X2 - 5x = 0

= − ( − 5 ) ±√ ( − 5 ) 2 − 4 ⋅ 1 ⋅0/2

= 5 ± 5 ÷ 2

= 5 + 5 ÷ 2

= 5 - 5 ÷ 2

= 5

= 0

2)   X2 - 16 = 0

= − 0 ± √0²  − 4 ⋅ 1( − 1 6 ) /2.1

= 0±8 ÷ 2

= 0+8÷2

= 0-8÷2

= 4

= -4

3)   X2 - 49 = 0

= − 0 ± √0 ² − 4 ⋅ 1 ( − 4 9 ) / 2 ⋅ 1

= 0 ±4÷2

= 0 + 14 ÷ 2

= 0 - 14 ÷ 2

= 7

= -7

4)   2x2 - 18 = 0

2 ( 2²− 9 )= 0

² - 9 = 0

= − 0 ± √0 ² − 4 ⋅ 1 ( − 9)/ 2.1

= 0 ±6÷2

= 0+6÷2

= 0-6÷2

=3

=-3

5)  3х2 - 11 = 0

= − 0 ±√ 0 ² − 4 ⋅ 3 ( − 1 1 )

= 0±2√33÷6

= 0+2√33÷6

= 0-2√33÷6

= √33÷3

= -√33÷3

6)   -X2 - x = 0

− ( ² + ) = 0

² += 0

= − 1 ±√ 1 ² − 4 ⋅ 1 ⋅ 0/ 2.1

=-1±1÷2

=-1+1÷2

=-1-1÷2

= 0

= -1

7)  -X2 + 12x = 0

− ( 2²− 1 2 ) = 0

² − 1 2 = 0

= − ( − 1 2 ) ±√ ( − 1 2 ) ² − 4 ⋅ 1 ⋅ 0

= 1 2 ± 1 2÷2

= 1 2 + 1 2÷2

= 1 2 − 1 2÷2

=12

= 0

8)   3x2 - 9x = 0

3 ( ² -3 )= 0

0 ² − 3 = 0

= − ( − 3 ) ±√ ( − 3 ) ²− 4 ⋅ 1 ⋅ 0

= 3 ± 3÷2

= 3 + 3÷2

= 3 − 3÷2

=3

=0

9)   X2 - 2x - 3 = 0

= − ( − 2 ) ±√ ( − 2 ) ² − 4 ⋅ 1 ( − 3 )

= 2 ± 4÷2

= 2 + 4÷2

= 2 - 4÷2

=3

= -1

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