Question

) 5-[7-2-(1-9)- 3 +12]+4 =
1-(-3 +6 +1)-[4-(6-3 + 1) - 2]=
6-(-9+7-1)-(3-(-5+4 +6)-1]=
28 - [21-12-3)-7]=
[-2+3.(2-5):3]-[(3 - 5+2)-2.(3-4)]=
8-[6-(-3 + 7)-6] +4 =
por Favor ​

Answer 1

primero se resuelven los () luego los [] y luego lo que sobra

*Ley de signos*

5-[7-2-(1-9)- 3 +12]+4 =

5-[7-2-(-8)-3+12]+4 =

5-[5-(-8)-3+12]+4 =

5-[-3-3+12]+4 =

5-[+6+12]+4 =

5-[+18]+4 =

+23+4 =

+27

1-(-3 +6 +1)-[4-(6-3 + 1) - 2]=

1-(7)-[4-(6-3 + 1) - 2] =

1-(7)-[4-(4)-2] =

1-(7)-[2] =

(-6)-2 =

+8

6-(-9+7-1)-[3-(-5+4 +6)-1] =

6-(-2-1)-[3-(-1+6)-1] =

6-(-3)-[3-(+5)-1] =

+3-[+8-1] =

+3-(+8) =

+5

28-[21-12(-3)-7] =

28-[-9(-3)-7] =

28-[-12(-7)] =

28-[-19] =

+9

[-2+3.(2-5):3]-[(3 - 5+2)-2.(3-4)]= está mal escrita

8-[6-(-3 + 7)-6] +4 =

8-[6-(+4)-6] +4 =

8-[+10-6] +4 =

8-[+4] +4 =

+12 +4 =

+16