Question

El ángulo que forma la recta l1, cuya pendiente es -1/3 con la recta l2, es de 135°. Calcular la pendiente de la recta l2.

Answer 1

$tan \alpha =[(m2-m1)/(1+(m2*m1))]$

m1 = -1/3

m2 = ?

$\alpha =135°$

tan(135) = -1

$-1 =[(m2-(-1/3))/(1+(m2*(-1/3))]]$

$-1 =[(m2+1/3))/(1-(1/3)m2))]$

-1(1 - (1/3)m2) = m2 + 1/3

-1 + (1/3)m2 = m2 + 1/3

-1 - 1/3 = m2 - (1/3)m2

-4/3 = 2/3m2

m2 = (-4/3)/(2/3) = -2

m2 = -2

La pendiente de I2 = -2