Question

SUMA
x+3y+x+2x–y+2z

(10³y²)+(4x³y²)+(2x³y²)

(6x+z) +(2x+3y) +(−y−5z) =

RESTA

(4x) – (–2x) =

(–2x) – (4x) =

(a) – (2a²) – (3b) =

(2x + 3x² – 4y) – (–4x²)

no quiero que comente cosa si no son la pregunta por que lo borrare

doy coroa es para mañana ayuda

Answer 1

SUMA

$x + 3y + x + 2x - y + 2z = 3x - 2y + 2z$

$( {10}^{3} {y}^{2} ) + (4 {x}^{3 } {y}^{2} ) + (2 {x}^{3} {y}^{2} ) \\ 100 {y}^{2} + 4 {x}^{3} {y}^{2} + 2 {x}^{3} {y}^{2} \\ 100 {y}^{2} + 6 {x}^{3} {y}^{2}$

$(6x + z) + (2x + 3y) + ( - y - 5z) \\ 6x + z + 2x + 3y - y - 5z \\ 8x + 2y - 6z$

RESTA

$(4x) - ( - 2x) = 4x + 2x = 6x$

$( - 2x) - (4x) = - 2x - 4x = 6x$

$(a) - (2 {a}^{2} ) - (3b) = a - 2 {a}^{2} - 3b$

$(2x + 3 {x}^{2} - 4y) - ( - 4 {x}^{2} ) \\ 2x + 3 {x}^{2} - 4y + 4 {x}^{2} \\ 7 {x}^{2} + 2x - 4y$