Question

Cuantos gramos de Carbono hay en 56 L de gas propano medido a 160°C y 600 Torr?

Answer 1

P x V = n x R x T

R = 0.0821 (atm. L/mol K)

T = 160 + 273 = 433 K

1 Atm. ---- 760 torr

    X     ----  600 torr

X = 0.789 atm.

n = P x V
     ``````````
       R x T

n =      0.789 atm x 56 L
        ````````````````````````````````````
       0.0821 /amt.L/mol K) 433 K

n = 1.242 mol

n (mol) = masa / Mm

masa C = n x  Mm

masa C = 1.242 mol x 12 g/mol

masas C = 14.904 g