Question

Ayuda, es sobre operaciones algebraicas

Answer 1

Respuesta:

1.  $-4x^{-3} \cdot(x^{5} -3x)$

$=-4\cdot \frac{1}{x^3}\left(x^5-3x\right)\\\\=-\frac{1\cdot \:4\left(x^5-3x\right)}{x^3}\\\\=-\frac{4\left(x^5-3x\right)}{x^3}\\\\=-\frac{4\left(x^4-3\right)}{x^2}$

2.  $8a^{7} b^{-5} x^{6} \cdot(-8abx^{9} +2a^{7} b^{8} x^{2} )$

$=8a^7\frac{1}{b^5}x^6\left(-8abx^9+2a^7b^8x^2\right)\\\\=\frac{1\cdot \:8a^7x^6\left(-8abx^9+2a^7b^8x^2\right)}{b^5}\\\\=\frac{8a^7x^6\left(-8abx^9+2a^7b^8x^2\right)}{b^5}\\\\=\frac{16a^8bx^8\left(-4x^7+a^6b^7\right)}{b^5}\\\\=\frac{16a^8x^8\left(-4x^7+a^6b^7\right)}{b^4}$

3.  $-7x^{8}\cdot(-17x^{8} -3x^{-7} y^{9} +5)$

$=-7x^8\left(-17x^8-\frac{3y^9}{x^7}+5\right)$

4.  $(11x^{9} y^{3} -3x^{-7} y^{9} )\cdot(4x^{-7} -5x^{5} y)$

$=\left(11x^9y^3-\frac{3y^9}{x^7}\right)\left(4x^{-7}-5x^5y\right)\\\\=\left(11x^9y^3-\frac{3y^9}{x^7}\right)\left(-5x^5y+\frac{4}{x^7}\right)$

5. $(12n^{5} m^{8} -2n^{-5} m^{-10} )\cdot(-14m^{4} -4mn+1)$

$=\left(12n^5m^8-\frac{2}{n^5m^{10}}\right)\left(-14m^4-4nm+1\right)$