Question

ayúdemen idenme plis ​

Answer 1

Aqui están

Explicación paso a paso:

1-) $-3(4-2x)+ (x+6)>6x-8$

$-3(4-2x)+ (x+6):$$\frac{13}{2}x-9$

$-3(4-2x)+\frac{1}{2}(x+6)$

$-3(4-2x): -12+6x$

$=-12+6x+\frac{1}{2}(x+6)$

$\frac{1}{2}(x+6): \frac{1}{2}x+3$

$=12+6x+\frac{1}{2}x+3$

$-12+6x+\frac{1}{2}x+3: \frac{13}{2}x-9$

=$=\frac{13}{2}x-9$

$\frac{13}{2}x-9>6x-8\frac{13}{2}x>6x+1\\\frac{13}{2}x-6x>6x+1-6x\\\frac{1}{2}x>1\\2*\frac{1}{2}x>1*2x>2$

Solución 1: x>2

2-) $\frac{1+x}{1-x}\geq 1$

$\frac{1+x}{1-x}\geq 1$ $1-1$

$\frac{1+x}{1-x}-1\geq 0$

$\frac{2x}{1-x}\geq 0$

$\frac{\frac{2x}{1-x} }{2}\geq \frac{0}{2}$

$\frac{x}{1-x}\geq 0$

$0\leq x< 1$

Solución 2: $0\leq x<1$

3-)  $\frac{6x-2}{5}<\frac{x}{2}-1$

$\frac{6x-2}{5}*10<\frac{x}{2}*10-1*10$

$2(6x-2)<5x-10$

$12x-4<5x-10$

$12x 4+4<5x-10+4$

$12x<5x-6$

$12x-5x<5x-6-5x$

$7x<-6$

$\frac{7x}{7}<\frac{-6}{7}$

$x<-\frac{6}{7}$

Solución 3: $x<-\frac{6}{7}$