Question

Ayúdenme porfa
(2r²+6r+ 7)+( 3r²+5r+8)​

Answer 1

Respuesta:

$\left(2r^2+6r+\:7\right)+\left(\:3r^2+5r+8\right)\\\\\\=2r^2+6r+7+3r^2+5r+8\\=2r^2+3r^2+6r+5r+7+8\\=5r^2+6r+5r+7+8\\=5r^2+11r+7+8\\=5r^2+11r+15$