Question

Resolver las siguientes ecuaciones:
a) x + 9x = 90
b) −2x + 1 = 3
c) 2(3x − 2) − (x − 3) = 8
d) 5(20 − x) = 4(2x − 1)

Answer 1

$x + 9x = 90 \\ 10x = 90 \\ x = \frac{90}{10} \\ x = 9$

$- 2x + 1 = 3 \\ - 2x = 3 - 1 \\ - 2x = 2 \\ x = \frac{2}{- 2} \\ x = - 1$

$2(3x - 2) - (x - 3) = 8 \\ 6x - 4 - (x - 3) = 8 \\ 6x - 4 - x + 3 = 8 \\ 6x - x = 8 + 4 - 3 \\ 5x = 9 \\ x = \frac{9}{5}$

$5(20 - x) = 4(2x - 1) \\ 100 - 5x = 4(2x - 1) \\ 100 - 5x = 8x - 4 \\ - 5x - 8x = - 4 - 100 \\ - 13x = - 104 \\ x = \frac{ - 104}{ - 13} \\ x = \frac{8}{1} \\ x = 8$

Espero ayudarte uwu