Question

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Answer 1

TEOREMA DE PITÁGORAS

${H}^{2} = {6}^{2} + {8}^{2} \\ {H}^{2} = 36 + 64 \\ {H}^{2} = 100 \\ H = \sqrt{100} \\ H = 10$

RESOLUCIÓN:

$M = ( \cot( \beta ) + \csc( \beta ) ) \\ M = \frac{8}{6} + \frac{10}{6} \\ M = \frac{18}{6} \\ M = 3$

RESPUESTA:

E) 3