Question

Me ayudan? Porfaaaaa

Answer 1

RESOLUCIÓN:

TEOREMA DE PITÁGORAS

${40}^{2} + {x}^{2} = {104}^{2} \\ 1600 + {x}^{2} = 10816 \\ {x}^{2} = 10816 - 1600 \\ {x}^{2} = 9216 \\ x = \sqrt{9216} \\ x = 96$

$x + y = 126 \\ 96 + y = 126 \\ y = 126 - 96 \\ y = 30$

${z}^{2} = {40}^{2} + {30}^{2} \\ {z}^{2} = 1600 + 900 \\ {z}^{2} = 2500 \\ z = \sqrt{2500} \\ z = 50$

RESPUESTA:

$Perímetro = 104 + 126 + 50 = 280$