Question

d) (2x - 3)(3x - 4) - (x - 13)(x – 4) = 40​

Answer 1

Respuesta:

(2x-3)(3x-4)-(x-13)(x-4)=40

(6x²-8x-9x+12)-(x²-4x-13x+52)=40

6x²-17x+12-x²+17x-52=40

5x²-40=40

5x²-80=0← Ecuacion Cuadratica.

Resuelto por Factorizacion.

Factor comun: 5

5(x²-16)=0

5(x+4)(x-4)=0

x₁+4=0

x₁=-4

x₂-4=0

x₂=4

Conjunto Solucion = (-4,4)

Espero que sirva

Answer 2

$(2x - 3)(3x - 4) - (x - 13)(x - 4) = 40$

$(6 {x}^{2} - 18x + 12) - ( {x}^{2} - 17x + 52) = 40$

$6 {x}^{2} - 18x + 12 - {x}^{2} + 17x - 52 = 40 \\ 5 {x}^{2} - x + </strong><strong>-</strong><strong> </strong><strong>4</strong><strong>0</strong><strong>= 40 \\ {5x}^{2} - x -</strong><strong> </strong><strong>8</strong><strong>0</strong><strong> = 0$