Question

7(x+3)-3(x-2)=16(2x-3)+19

Answer 1

7(x+3)-3(x-2)=16(2x-3)+19
7x+21-3x+6=32x-48+19
21+48-19+6= -7x+3x+32x
56 = 28x
x = 56/28
X = 2

7(x+3)-3(x-2)=16(2x-3)+19
7x+21-3x+6=32x-48+19
7x-3x-32x= -6-48-21+19
-28x= -35
x= -56/-28
X = 2