Question

Ayudenme a resolver esta ecuaciones de 2grado

Answer 1

X² - 8X + 15 = 0; Donde a = 1; b = - 8; c = 15

$X=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$


 $X=\frac{-(-8)\pm \sqrt{(-8)^2-4(1)(15)}}{2(1)}$

$X=\frac{8\pm \sqrt{64-60}}{2}$

$X=\frac{8\pm \sqrt{4}}{2}$

$X=\frac{8\pm \ 2}{2}$

X1 = [8+2]/2 = 5

X2 = [8 - 2]/2 = 3

X = 5 y X = 3