El ácido nítrico comercial, que se vende a una concentración 16 mol/L, tiene una densidad de 1,42 g/mL. El % en masa del HNO3 (M: 63,02 g/mol) en la disolución es:

Respuestas

Respuesta dada por: Nahuel0311

Respuesta:

%m/m= (gr sto / gr sl).100

16 moles --> 1000 ml

1,6 moles --> 100 ml

1 mol sto --> 63,02 g sto

1,6 moles sto --> 100,832 g sto

m de solucion=1,42 g /ml . 100,832 g = 143,18 g

%m/m=(100,832 g sto / 143,18 g sl).100=70,423%

Respuesta dada por: elgabriel1940

Respuesta:

nose

Explicación:

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