Question

procedimiento
(x+2)(x+4)=
(x+2)(x-4) =
(x-2)(x+4) =
(x-2)(x-4) =​

Answer 1

Respuesta:

(x+2)(x+4)=

$x^{2}$+4x+2x+8

$x^{2}$ +(4x+2x)+8

$x^{2}$+6x+8

___________________________

(x+2)(x-4) =

$x^{2}$−4x+2x−8

$x^{2}$+(−4x+2x)−8

$x^{2}$−2x−8

___________________________

(x-2)(x+4) =

$x^{2}$+4x−2x−8

$x^{2}$+(4x−2x)−8

$x^{2}$+2x−8

____________________________

(x-2)(x-4) =​

$x^{2}$−4x−2x+8

$x^{2}$+(−4x−2x)+8

$x^{2}$−6x+8

ya esta uwu

Answer 2

Respuesta:

(x-2)(x-4) =​