Question

reduce el siguinte perimetro 3×^2-4×+8 y -5×^3-4×^2-7 de un rectángulo​

Answer 1

Respuesta:

2 - 16$x^{10}$

Explicación paso a paso:

3$x^{2}$ - 4x + 8

  x + 8

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-5$x^{3}$ - 4 $x^{2}$ - 7

- 9$x^{5}$ - 7

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La formula del perímetro de un rectángulo es:

2(h+b)

entonces vamos a reemplazar

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2( x + 8+ ( - 9$x^{5}$ - 7 ))

2( x + 8 - 9$x^{5}$ - 7 )

2 ( x + 1 - 9$x^{5}$ )

2 ( 1 - 8$x^{5}$ )

2 - 16$x^{10}$

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Espero de algo te ayude mi respuesta c':