Question

(x³+5x²+x-1) : ( x-2)
como se hase​

Answer 1

Respuesta:

$\left(x^3+5x^2+x-1\right):\left(\:x-2\right)$

Dividimos

$\frac{\left(x^3+5x^2+x-1\right)}{\left(x-2\right)}=x^2+\frac{7x^2+x-1}{x-2}$

$\frac{7x^2+x-1}{x-2}=7x+\frac{15x-1}{x-2}$

$x^2+7x+\frac{15x-1}{x-2}$

Solución

$\frac{15x-1}{x-2}=15+\frac{29}{x-2}$

$\boxed{x^2+7x+15+\frac{29}{x-2}}$

Saludos...