separar en términos.
A
(120 \div 15 + 1) \times 4 - 102 \div 6 + 5 =
B
(4 + 7 \times 4) \div 4 \times 2 + 15 \times 7 - 11 \times 11 =
C
18  \times 14 \div 6 - (63 \div 7 + 1) \times 2 \times 2 =
D
315 \div 9 - (8 + 5 \times 20) \div 12 - 5 \times 5 =
E
(108 \div 6 - 3) \times 7 - 4  \times (3 \times 5 - 5) + 156 \div 12 - 9 =
F
6 \times (3 \times 3 + 2 \times 5) - (119 \div 7 - 4) \times 8 + 168 \div 12 - 11 =
G
(128 \div 8 + 54 \div 6) \div 5 + (4 \times 2 + 2 \times 3) \times 7 - 198 \div 11 \div 3 =
H
3 \times  {2}^{3}  -  \sqrt{9 + 5 \times 8}  + ( {4}^{2} + 4) \div  \sqrt{100}   - 7 =
J
(25 - 4 \times 3) ^{2}  -  {8}^{2}  +  \sqrt[3]{100 + 25}  + 12 \div 3 =

Respuestas

Respuesta dada por: jhonmarcillo79
0

Explicación paso a paso:

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