Question

Lo necesito hoy Ayuda! ​

Answer 1

Respuesta:

$a)\\ x = - 2 \\ y = 6 \times ( - 2) - 1 = - 12 - 1 = - 13 \\ \\ x = 3 \\ y = 6 \times 3 - 1 = 18 - 1 = 17 \\ \\ x = 0 \\ y = 6 \times 0 - 1 = 0 - 1 = - 1$

$b) \\ x = - 2 \\ y = {( - 2)}^{2} + ( - 2) - 2 = 4 + ( - 2) - 2 = 4 - 2 - 2 = 0 \\ \\ x = 3 \\y = {3}^{2} + 3 - 2 = 9 + 3 - 2 = 10 \\ \\ x = 0 \\y = {0}^{2} + 0 - 2 = - 2$

$c) \\ x = - 2 \\y = 2 \times {( - 2)}^{3} - 4 \times ( - 2) = 2 \times ( - 8) - ( - 8) = - 16 - ( - 8) = - 16 + 8 = - 8 \\ \\ x = 3 \\ y = 2 \times {3}^{3} - 4 \times 3 = 2 \times 27 - 4 \times 3 = 54 - 12 = 42 \\ \\ x = 0 \\ y = 2 \times {0}^{3} - 4 \times 0 = 0$

$d) \\ x = - 2 \\ y = \frac{ - 2 +5 }{2} = \frac{3}{2} \\ \\ x = 3 \\ y = \frac{3 + 5}{2} = \frac{8}{2} = 4 \\ \\ x = 0 \\ y = \frac{0 + 5}{2} = \frac{5}{2}$

$e) \\ x = - 2 \\ y = {( - 2 - 1)}^{2} = {( - 3)}^{2} = 9 \\ \\ x = 3 \\ y = {(3 - 1)}^{2} = {2}^{2} = 4 \\ \\ x = 0 \\ y = {(0 - 1)}^{2} = {( - 1)}^{2} = 1$

$f) \\ x = - 2 \\ y = \frac{3 \times {( - 2)}^{2} + 2}{ - 2} = \frac{3 \times 4 + 2}{ - 2} = \frac{14}{ - 2} = - 7 \\ \\ x = 3 \\ y = \frac{3 \times {3}^{2} + 2}{3} = \frac{3 \times 9 + 2}{3} = \frac{29}{3} \\ \\ x = 0 \\ y = \frac{3 \times {0}^{2} + 2 }{0} ⇒no \: \: puede \: \: ser ,porque \: \: divisor \: \: no \: \: puede \: \: ser \: \: 0$