Question

Ecuación lineales incógnita y comprobación :
4m+8=8m+2
3n+40=12n-14
5m-6=7m-10-4
3.5x+8=6.5x-4
2f-4=6f-32
20-7+2=10x+5
6p-5=8p+2
4x+2+9x+18=12(x+2)
-3x+2=x+10
-6d+3=-2d+1
-2(8c+5)=5(3c+4)​

Answer 1

Respuesta:

$4m + 8 = 8m + 2 \\ 8 - 2 = 8m - 4m \\ 6 = 4m \\ \frac{6}{4} = m \\ \frac{3}{2} = m$

$3n + 40 = 12n - 14 \\ 40 + 14 = 12n - 3n \\ 54 = 9n \\ \frac{54}{9} = n \\ 6 = n$

$5m - 6 = 7m - 10 - 4 \\ 5m - 6 = 7m - 14 \\ - 6 + 14 = 7m - 5m \\ 8 = 2m \\ \frac{8}{2} = m \\ 4 = m$

$3 \times 5x + 8 = 6 \times 5x - 4 \\ 15x + 8 = 30x - 4 \\ 8 + 4 = 30x - 15x \\ 12 = 15x \\ \frac{12}{15} = x \\ \frac{4}{5} = x$

$2f - 4 = 6f - 32 \\ - 4 + 32 = 6f - 2f \\ 28 = 4f \\ \frac{28}{4} = f \\ 7 = f$

$20 - 7 + 2 = 10x + 5 \\ 15 = 10x + 5 \\ 15 - 5 = 10x \\ 10 = 10x \\ 1 = x$

$6p - 5 = 8p + 2 \\ - 5 - 2 = 8p - 6p \\ - 7 = 2p \\ - \frac{7}{2} = p$

$4x + 2 + 9x + 18 = 12(x + 2) \\ 13x + 20 = 12x + 24 \\ 13x - 12x = 24 - 20 \\ x = 4$

$- 3x + 2 = x + 10 \\ 2 - 10 = x + 3x \\ - 8 = 4x \\ - \frac{8}{4} = x \\ - 2 = x$

$- 6d + 3 = - 2d + 1 \\ 3 - 1 = - 2d + 6d \\ 2 = 4d \\ \frac{2}{4} = d \\ \frac{1}{2} = d$

$- 2(8c + 5) = 5(3c + 4) \\ - 16c - 10 = 15c + 20 \\ - 10 - 20 = 15c + 16c \\ - 30 = 31c \\ - \frac{30}{31} = c$