Question

Sean
F(x)= x^2-3
G(x)=2x+8
H(x)=4x^3+3
Determina:
::(f+g)(3)

::(f/h)(3)+(g)(-1)

Answer 1

 (f+g)(3)=f(3)+g(3)=(3^2-3)+(2*3+8)=6+14=20

(f/h)(3)+g(-1)=(f(3)/h(3))+g(-1)=(6/111)+(6)=(2/37)+6=224/37

Answer 2

(F+G)(3)=
(3²-3)+(2*3+8)
20

(F/H)(3)+(G)(-1)=
((3²-3)/(4*3³+3))+(2*(-1)+8)
(6/111)+6
672/11