Question

ayudaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Answer 1

sec53=$\frac{5}{3}$

ahora=ctgx=$\frac{5}{3}$

ctg=$\frac{Ca}{Co}$

sen=$\frac{Co}{H}\\5^{2}+3^{2}=H\\H=\sqrt{34}$

reemplazamos:

$\sqrt{34} .senx+6.\frac{5}{3}$

34+10=44

RPTA:44