Question

ayuda porfa es para hoy ​

Answer 1

                SISTEMA DE ECUACIONES

                        $\Large\boxed{\mathbf{\left \{ {{5x-4y=4} \rightarrow 1^o~ecuaci\'on \atop {4x-4y=24\rightarrow 2^o~ecuaci\'on}} \right. }}$

Vamos a despejar x en las 2 ecuaciones.

$\red{\Large\textbf{Primera ecuaci\'on}}\\\\\mathrm{5x-4y=4}\\\\\mathrm{5x=4+4y}\\\\\boxed{\mathrm{x=\dfrac{4+4y}{5} }}$

$\red{\Large\textbf{Segunda ecuaci\'on}}\\\\\mathrm{4x-4y=24}\\\\\mathrm{4x=24+4y}\\\\\boxed{\mathrm{x=\dfrac{24+4y}{4} }}$

E igualamos.

$\mathrm{\dfrac{4+4y}{5}=\dfrac{24+4y}{4} }\\\\\mathrm{4(4+4y)=5(24+4y)}\\\\\mathrm{16+16y=120+20y}\\\\\mathrm{16-120=20y-16y}\\\\\mathrm{16-120=20y-16y}\\\\\mathrm{-104=4y}\\\\\Large\boxed{\mathbf{-26=y}}$

Ahora hallamos x, para eso vamos a despejar en la primera ecuación.

$\mathrm{5x - 4y = 4}\\\\\mathrm{5x - 4(-26) = 4}\\\\\mathrm{5x - (-104) = 4}\\\\\mathrm{5x + 104 = 4}\\\\\mathrm{5x = 4 - 104}\\\\\mathrm{5x = -100}\\\\\Large\boxed{\mathbf{x=-20}}$

RPTA: x = -20, y = -26

Saludos, Math_and_fisic_girl