Question

me pueden ayudar paso por paso pls

Answer 1

b)

$- \frac{1}{3} \times (x + \frac{1}{5} ) + \frac{1}{2} \times (x - 2) = - \frac{1}{5} \times ( - 3 + x) + \frac{1}{2} \\ \frac{ - 2( x + \frac{1}{5}) + 3(x - 2)}{6} = \frac{ - 2( - 3 + x) + 5}{10} \\ \frac{ - 2x - \frac{2}{5} + 3x - 6}{6} = \frac{6 - 2x + 5}{10} \\ \frac{x - 6 + \frac{ - 2}{5} }{6} = \frac{11 - 2x}{10} \\ \frac{x + \frac{ - 32}{5} }{3} = \frac{11 - 2x}{5} \\ 5(x + \frac{ - 32}{5} ) = 3(11 - 2x) \\ 5x - 32 = 33 - 6x \\ 5x + 6x = 33 + 32 \\ 11x = 65 \\ x = \frac{65}{11}$

$\frac{4}{9} ( \frac{3}{8} x - \frac{27}{16} ) - \frac{3}{4} x + 1 = \frac{1}{3} \\ \frac{4 \times 3x}{9 \times 8} - \frac{4 \times 27}{9 \times 16} - \frac{3}{4} + 1 = \frac{1}{3} \\ \frac{x}{6} - \frac{3}{4} - \frac{3}{4} = \frac{1}{3} - 1 \\ \frac{x}{6} - \frac{6}{4} = \frac{ - 2}{3} \\ \frac{x}{6} = \frac{ - 2}{3} + \frac{6}{4} \\ \frac{x}{6} = \frac{ - 8 + 18}{12} \\ \frac{x}{1} = \frac{ 10}{2} \\ x = 5$