Question

(3x-7)/12=(1/6(2x-3))-(x-1)/8 ayudenme porfa

Answer 1

$\frac{3x - 7}{12} = \frac{(\frac{1}{6(2x - 3)} ) - (x - 1)}{8} \\ \frac{3x - 7}{3} = \frac{(\frac{1}{6(2x - 3)} ) - (x - 1)}{2} \\ 2(3x - 7) = 3(\frac{1}{6(2x - 3)} ) - (x - 1)) \\ 6x - 14 = \frac{1}{2(2x - 3)} - 3(x - 1) \\ 6x - 14 + 3x - 3 = \frac{1}{4x - 6} \\ 9x - 17 = \frac{1}{4x - 6} \\ (9x - 17)(4x - 6) = 1 \\ 36 {x}^{2} - 54x - 68x + 102 = 1 \\ 36 {x}^{2} - 122x + 101 = 0$