Question

si M=2³×7¹×11⁴^n tiene 40 divisores, hallar "n"

a)1
b)2
c)3
d)4
e)5

AYUDA PORFIS​

Answer 1

Respuesta:

$n = {x}^{a} \\ CD(M) = (3+1 ) (1+1)(4+1) (a+1 ) = 40 \\ = (4)(2)(5)(a + 1) = 40 \\ (a + 1) = \frac{40}{40} =1 \\ a + 1 = 1 \\ a = 0 \\ n = {x}^{0} \\ n = 1$

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