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Hay que racionalizar el denominador, es decir, eliminar la raíz que contiene.
![\frac{14}{3- \sqrt{2} } = \frac{14*(3+ \sqrt{2}) }{(3- \sqrt{2})*(3+ \sqrt{2} } = \frac{14*(3+ \sqrt{2})}{9-2} = \frac{14*(3+ \sqrt{2})}{7} =2*(3+ \sqrt{2})= \\ \\ =6+2 \sqrt{2} \frac{14}{3- \sqrt{2} } = \frac{14*(3+ \sqrt{2}) }{(3- \sqrt{2})*(3+ \sqrt{2} } = \frac{14*(3+ \sqrt{2})}{9-2} = \frac{14*(3+ \sqrt{2})}{7} =2*(3+ \sqrt{2})= \\ \\ =6+2 \sqrt{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B14%7D%7B3-+%5Csqrt%7B2%7D+%7D+%3D+%5Cfrac%7B14%2A%283%2B+%5Csqrt%7B2%7D%29+%7D%7B%283-+%5Csqrt%7B2%7D%29%2A%283%2B+%5Csqrt%7B2%7D+%7D+%3D+%5Cfrac%7B14%2A%283%2B+%5Csqrt%7B2%7D%29%7D%7B9-2%7D+%3D+%5Cfrac%7B14%2A%283%2B+%5Csqrt%7B2%7D%29%7D%7B7%7D+%3D2%2A%283%2B+%5Csqrt%7B2%7D%29%3D+%5C%5C++%5C%5C+%3D6%2B2+%5Csqrt%7B2%7D++)
Saludos.
Saludos.
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