Question

ayuda por favor determina el valor de la incognita en la ecuacion
16c ala 2+40c+25=0
16a ala 2+48a+36=0

Answer 1

$16c^{2} +40c+25 = 0$
4c                     +5
4c                     +5

20c+20c = 40c

(4c+5)(4c+5) =0

4c +5 = 0
4c = -5
c = -5/4

CS = (-5/4)


$16c^{2}+48c+36 = 0$
4c                    +6
4c                    +6

24c + 24c = 48c

(4c+6)(4c+6) = 0

4c+6 = 0
4c = -6
c = -6/4
c = -2/3

CS= (-2/3)