Question

resolver las siguientes fracciones con potencias
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Answer 1

Respuesta:

a) 81/625

b) 8/27

c) 1/64

Explicación paso a paso:

a) (3)⁴/(-5)⁴ = 3x3x3x3/ (-5)(-5)(-5)(-5) = 81/625

b) (4/6)³ = (2/3)³ = 2³/3³ = 2x2x2/3x3x3 = 8/27

c) (-2/4)⁶ = (-1/2)⁶ = (-1)(-1)(-1)(-1)(-1)(-1)/(2)(2)(2)(2)(2)(2) = 1/64