Question

ayuda (doy coronaa)​

Answer 1

$p(a) = - 2 {a}^{2} + 5a + 3 = - (2 {a}^{2} - 5a - 3) = - (2a + 1)(a - 3)$

$q(z) = 1 - {z}^{2} = (1 + z)(1 - z)$

$r(x) = {x}^{3} - x + 1 = x(x + 1)(x - 1) + 1$

• -1

P(a)= - [(2(-1) +1)(-1-3)] = - [(-2+1)(-4)] =-[(- 1)(-4)] = -4

Q(z)=( 1-1)(1- (-1)) =0

R(x)= - 1(-1+1)(-1-1) +1= +1

• 2

P(a)= - [(2(2) +1)(2-3)] = - [(5)(-1)] = 5

Q(z)=( 1+2)(1- 2) =(3)(-1)= -3

R(x)= 2(2+1)(2-1) +1= 2(3)(1)+1= 6+1=7

• 1/2

P(a)= - [(2(1/2) +1)(1/2-3)] = - [(2+1) ((1-6)/2)] = - [(3)(-5/2)] = 15/2

Q(z)=( 1+1/2)(1- 1/2) =((2+1)/2) ((2-1)/2)= (3/2)(1/2) =3/4

R(x)= 1/2(1/2+1)(1/2-1) +1= 1/2(( 1+2)/2)) ((1-2)/2) +1= 1/2(3/2)(-1/2) +1= - 3/8 +1= (-3+8)/8= 5/8

• 0

P(a)= - [( 2(0) +1)(0-3)] = - [(1)(-3)] = 3

Q(z)=( 1+0)(1- 0) =(1) (1)= 1

R(x)= 0(0+1)(0-1) +1= +1