Question

hallar la hipotenusa de los siguientes triangulos rectangulos​

Answer 1

${y}^{2} = {a}^{2} + {b}^{2} \\ {y}^{2} = {16}^{2} + {6}^{2} \\ {y}^{2} = 256 + 36 \\ {y}^{2} = 292 \\ y = 2 \sqrt{73}$

Answer 2

Respuesta:

$y^{2}$ = $a^{2}$ + $b^{2}$

$y^{2}$ = $16^{2}$ + $6^{2}$

$y^{2}$ = $256$ + $36$

$y^{2}$ = $292$

$y$ = $\sqrt{292}$

$y$ = $17.08$