Question

3 x ^ { 2 } + 2 x - 8 = 0​

Answer 1

¡Hola!

$\bold{Trinomio \ de \ la \ forma \ ax^{2} +bx+c.}$

$3 {x}^{2} + 2x - 8 = 0 \\ \\ \\ 3{x}^{2} - 4x + 6x - 8 = 0 \\ \\ \\ (3 {x}^{2 } - 4x) + ( 6x - 8) = 0 \\ \\ \\ x( 3x - 4) + 2(3 x - 4) = 0 \\ \\ \\ \boxed{\gray{(3x - 4)(x + 2)} = 0}$

.

$x_{1} \\ \\ (3x - 4) \\ \\ \\ 3x - 4 = 0 \\ \\ \\ 3x = 4 \\ \\ \\ \boxed{x = \dfrac{4}{3} }$

.

$x_{2} \\ \\ (x + 2) \\ \\ \\ x + 2 = 0 \\ \\ \\ \boxed{ x = - 2}$

Espero que sirva y saludos.