Question

HALLE EL VALOR DEL LADO FALTANTE APICANDO PITÁGORAS


resuelva con su respectivo proceso,TODO EN CENTIMETROS X ES EL VALOR QUE DEBEMOS HALLAR.

Answer 1

Respuesta:

Explicación paso a paso:

1.-----------------//--------------

$h = \sqrt{Cad^2 + Cop^2} \\h^2 - Cad^2 = Cop^2\\\sqrt{25^2-24^2} = x\\7 = x$

2.-------------//----------------

$h = \sqrt{Cad^2 + Cop^2} \\h^2 - Cad^2 = Cop^2\\ \sqrt{29^2-21^2} = x\\20 = x$

3-------------------------//-------

$h = \sqrt{Cx^2 + Cy^2} \\h^2 - Cx^2 = Cy^2\\ \sqrt{13^2-5^2} = x\\12 = x$

4-------------------------//-------

$h = \sqrt{Cx^2 + Cy^2} \\h^2 - Cx^2 = Cy^2\\ \sqrt{25^2-24^2} = x\\7 = x$

5-------------------------//-------

$h = \sqrt{Cx^2 + Cy^2} \\h= \sqrt{16^2+12^2} \\h= 20 = x$

6-------------------------//-------

$h = \sqrt{Cx^2 + Cy^2} \\h^2 - Cx^2 = Cy^2\\ \sqrt{10^2-6^2} = x\\8 = x$

7-------------------------//-------

$h = \sqrt{Cx^2 + Cy^2} \\ \sqrt{21^2+20^2} = x\\h= 29 = x$

8-------------------------//-------

$h = \sqrt{Cx^2 + Cy^2} \\ \sqrt{12^2+9^2} = x\\h=15 = x$

9-------------------------//-------

$h = \sqrt{Cx^2 + Cy^2} \\h^2 - Cx^2 = Cy^2\\ C= \sqrt{15^2-9^2} = x\\12 = x$

10-------------------------//-------

$h = \sqrt{Cx^2 + Cy^2} \\h^2 - Cx^2 = Cy^2\\Cy= \sqrt{17^2-15^2} = x\\8 = x$

11-------------------------//-------

$h = \sqrt{Cx^2 + Cy^2} \\h^2 - Cx^2 = Cy^2\\ \sqrt{10^2-6^2} = x\\8 = x$

12-------------------------//-------

$h = \sqrt{Cx^2 + Cy^2} \\ \sqrt{35^2+12^2} = x\\h=15 = x$