Respuestas
Respuesta dada por:
0
X = Numero Menor
Y = Numero Mayor
X + Y = 40; Y = 40 - X
Condicion
(2/7)Y = (2/3)X
(2/7)(40 - X) = (2/3)X
80/7 - (2/7)X = (2/3)X
80/7 = (2/3)X + (2/7)X
![\frac{80}{7}= \frac{14+6}{21}X \frac{80}{7}= \frac{14+6}{21}X](https://tex.z-dn.net/?f=+%5Cfrac%7B80%7D%7B7%7D%3D+%5Cfrac%7B14%2B6%7D%7B21%7DX++)
![\frac{80}{7}= \frac{20}{21}X \frac{80}{7}= \frac{20}{21}X](https://tex.z-dn.net/?f=+%5Cfrac%7B80%7D%7B7%7D%3D+%5Cfrac%7B20%7D%7B21%7DX++)
(80)(21) = (7)(20)X
1680 = 140X
X = (1680)/(140) = 12
X = 12
Y = 40 - X; Y = 40 - 12 = 28
Los numeros son 28 y 12
Y = Numero Mayor
X + Y = 40; Y = 40 - X
Condicion
(2/7)Y = (2/3)X
(2/7)(40 - X) = (2/3)X
80/7 - (2/7)X = (2/3)X
80/7 = (2/3)X + (2/7)X
(80)(21) = (7)(20)X
1680 = 140X
X = (1680)/(140) = 12
X = 12
Y = 40 - X; Y = 40 - 12 = 28
Los numeros son 28 y 12
Preguntas similares
hace 6 años
hace 9 años
hace 9 años
hace 9 años