Question

la suma de 2 numeros es 40 y 2/7 del mayor equivalen a 2/3 del menor. halle los numeros

Answer 1

X =  Numero Menor
Y =  Numero Mayor

X + Y = 40;  Y = 40 - X

Condicion

(2/7)Y = (2/3)X

(2/7)(40 - X) = (2/3)X

80/7 - (2/7)X = (2/3)X

80/7 = (2/3)X + (2/7)X


$\frac{80}{7}= \frac{14+6}{21}X$

$\frac{80}{7}= \frac{20}{21}X$

(80)(21) = (7)(20)X

1680 = 140X

X = (1680)/(140) = 12

X = 12

Y = 40 - X;  Y = 40 - 12 = 28

Los numeros son 28 y 12