Question

ayuda ;-;
me ayudan plis
les doy corona ​

Answer 1

Procedimiento:

a)

$\sqrt{25 + 16} + 2 ^{3} - (3 + \sqrt{4} )\\ \sqrt{25 - 16} + 8 - (3 + 2) \\ \sqrt{25 - 16} + 8 - 5 \\ \sqrt{9} + 3 \\ 3 + 3 \\ = 6$

b)

$(2 + \sqrt{49} + 4 - \sqrt{4} ) ^{2} \\ (2 + 7 + 4 - 2)^{2} \\ = {11}^{2} \\ = 121$

c)

$\sqrt{10 ^{2} \div 4} + \sqrt{5 ^{3} \div {5}^{3} } \\ \\ \sqrt{ \frac{10 ^{2} }{4} } + \sqrt{1} \\ \\ \frac{10}{2} + 1 \\ \\ 5 + 1 = 6$

d)

$\sqrt{ \sqrt{16} } + {2}^{2} - 7 ^{0} + 0 \\ \sqrt{4} + 4 - 1 \\ 2 + 4 - 1 \\ = 5$

e)

$(10 ^{2}) ^{2} - 10 ^{2} \times 10 \\ {10}^{4} - {10}^{3} \\ (10 - 1) \times {10}^{3} \\ 9 \times 1000 \\ = 9000$

Espero que te ayude!